Question : How much positive and negative charge is there in a cup of water?
Doubt by Palak
Solution :
Let us assume that mass of water in a cup will be 250 g
Let us assume that mass of water in a cup will be 250 g
Molecular Mass of Water (H2O) is 18 u
So mass of 1 mole of water molecule is 18 g
No. of moles = Given Mass / Molar Mass
n = 250/18
So mass of 1 mole of water molecule is 18 g
No. of moles = Given Mass / Molar Mass
n = 250/18
No. Molecules in 1 moles = 6.02×1023.
∴ No. of molecules of Water in (250/18) moles
∴ No. of molecules of Water in (250/18) moles
= (250/18)×6.02×1023
In 1 molecules of water, there would be 10(2×1+8) Positive charge (Protons) and 10 Negative charge (electrons).
In 1 molecules of water, there would be 10(2×1+8) Positive charge (Protons) and 10 Negative charge (electrons).
Total Number of Positive and Negative charge in a cup of water (N)
= (250/18)×6.02×1023×10
∴ Both will have same magnitude. So, Magnitude of each type of charge (q)
=Ne
= (250/18)×6.02×1023×10×1.6×10-19
= 1.34×107C
= (250/18)×6.02×1023×10
∴ Both will have same magnitude. So, Magnitude of each type of charge (q)
=Ne
= (250/18)×6.02×1023×10×1.6×10-19
= 1.34×107C
Similar Question :
A cup contains 250 g of water. The number of negative charges present in the cup of water is
a) 1.34 × 107 C
b) 1.34 × 1019 C
c) 3.34 × 107 C
d) 1.34 × 10-19 C
Doubt by Nisha
Ans :
a) would be the correct option.
