Question : A long straight wire in the horizontal plane carries a current of 50 A in north to south direction. Give the magnitude and direction of B at a point 2.5 m east of the wire.
Doubt by Deepanshi U.
Solution :
We know,
Magnetic Field due to a straight current carrying conductor is given by
B = μI₀/2πr
Here
I = 50 A [Flowing from North to south]
r = 2.5 m [East]
B = μI₀/2πr
B = 2μI₀/4πr
B = (2 × 50 × 10-7)/2.5
B = 40 × 10-7
B = 4 × 10-6 T
By Applying the Fleming's Left Hand Rule, we can easily find that the direction of magnetic field in upward.
