Question : You are given three lenses L1, L2, L3 each of focal length 20 cm. An object is kept at 40 cm in front of L1. The final real image is formed at the focus I of L3. Find the separation between L1, L2 and L3.
Doubt by Eshani
Solution :
f1=f2=f3=+20 cm
For Lens L1
u1=-40 cm
u1=-40 cm
f1=+20 cm
Using Thin Lens Formula
Now,
v1=u1f1/(u1+f1)
v1=(-40)(20)/(-40+20)
v1=-800/-20
v1=40 cm
v1=-800/-20
v1=40 cm
For Lens L3
v3=+20 cm
f3=+20 cm
Now,
u3=v3f3/(f3-v3)
u3=(20)(20)/(20-20)
u3=400/0
u3=∞
u3=(20)(20)/(20-20)
u3=400/0
u3=∞
For Lens L2
v2=+∞
f2=+20 cm
1/20=1/∞-1/u2
1/20=-1/u2
1/20=-1/u2
u2=-20 cm
Hence, distance between L1 and L2 is given by
= |v1|+|u2|
= |40|+|-20|
= 40+20
= 60 cm
= |40|+|-20|
= 40+20
= 60 cm
Distance between L2 and L3 is given by
=|v2|+|u3|
=|v2|+|u3|
=|∞| + |∞|
= ∞
= ∞
Hence, the distance between L2 and L3 could be any distance. The exact distance between the Lens L2 and L3 can't be calculated.
Similar Question :
You are given three lenses L1, L2 and L3 each of focal length 10 cm. An Object is kept at 15 cm in front of L1, as shown. The final real image is formed at the focus 'F' of L3. Find the separations between L1, L2 and L3.
Doubt by Sonali

Ans :
Distance between L1 and L2 = 40 cm
Distance between L2 and L3 = ∞ [Can't be exactly calculated]