Question : A circular coil of cross-sectional area 200 cm² and 20 turns is rotated about the vertical diameter with an angular speed of 50 rad/s, in a uniform magnetic field of magnitude 3×10-2 T. Calculate the maximum value of the current in the coil. [Take resistance of the coil equal to 20Ω]
Doubt by Angad
Solution :
Area of cross section (A)
= 200 cm²
= 200×10-4 m²
= 200 cm²
= 200×10-4 m²
= 0.02 m²/
Number of Turns (N) = 20
Angular velocity (⍵) = 50 rad/s
Magnitude of Magnetic Field (B) = 3×10-2 T
Resistance of coil (R) = 20Ω
Emf Induced (ε) = NA⍵Bsinθ
Maximum Emf Induced (εmax) = NA⍵B
Maximum Current Induced (Imax)
=εmax/R
= NA⍵B/R
= [20×0.02×50×3×10-2]/20
= 0.6/20
= 0.3/10
= 0.03 A
Maximum Emf Induced (εmax) = NA⍵B
Maximum Current Induced (Imax)
=εmax/R
= NA⍵B/R
= [20×0.02×50×3×10-2]/20
= 0.6/20
= 0.3/10
= 0.03 A
Hence, the maximum value of induced current in the coil is 0.03 A
