In a parallel plate capacitor the potential difference . . .

Question : In a parallel plate capacitor the potential difference of 100 V is maintained between the plates. If the distance between the plates be 5 mm, what is the electric field at points A and B?

Doubt by Angad

Solution : 
We know, the electric field between the plates of capacitor is uniform so the value of electric field at point A and B will remain the same. 
The magnitude of electric field is given by 
Electric field = Potential / Distance

Here, 
V = 100 V

d = 5 mm

   = 5×10^-3 m

E_A=E_B=100/(5×10^-3)
E_A=E_B=(100×10³)/5
E_A=E_B=20×10³ V/m
E_A=E_B=2×10⁴ V/m