(A) 0.1 mA
(B) 1 mA
(C) 10 mA
(D) 0.1 A
Doubt by Somya
Solution :
Doubt by Somya
Solution :
G=100Ω
I=1 A
I=1 A
S=0.1Ω
Ig=?
We know,
S=GIg/I-Ig
S(I-Ig)=GIg
SI-SIg=GIg
SI=GIg+SIg
SI=Ig(G+S)
Ig=SI/(G+S)
Ig=(0.1)(1)/(100+0.1)
Ig=0.1/100.1
Ig≈0.1/100
Ig≈0.001
Ig≈1mA.
Hence, (B) 1 mA, would be the correct option.
Ig=?
We know,
S=GIg/I-Ig
S(I-Ig)=GIg
SI-SIg=GIg
SI=GIg+SIg
SI=Ig(G+S)
Ig=SI/(G+S)
Ig=(0.1)(1)/(100+0.1)
Ig=0.1/100.1
Ig≈0.1/100
Ig≈0.001
Ig≈1mA.
Hence, (B) 1 mA, would be the correct option.