Doubt by CBSE
Solution :
Two point charges of 10µC and -5µC are placed at . . .
Question : Two point charges of 10µC and -5µC are placed at (-3cm, 0) and (6cm, 0) in an external electric field E=A/r², where A=1.8×10^5 Nm²/C. Calculate the electrostatic energy of the system.
