Question : An inductor, a resistor and a capacitor are connected in series to an ac source. If the frequency of ac source is greater than the resonant frequency then current in the circuit
a) leads the voltage
b) lags behind the voltage
c) is in same phase with the voltage
d) none of the above.
Doubt by Deepanshi
Solution :
Here
ν>ν₀ (Given)
2πν>2πν₀
ω>ω₀
ω>1/√(LC)
ω2>1/LC
ωL>1/ωC
XL>XC
This is the condition for inductive circuit and we know in inductive circuit current lag behind the voltage. Hence, the correct option is ✔️ b) lags behind the voltage
Similar Question :
An a.c voltage ε = ε₀sinωt, is applied across a series combination of an inductor L, capacitor C and resistor R.Use phasor diagram to obtain expression for the a) impedance of the circuit, and b) phase angle between the applied voltage and the resulting current in the circuit. Hence show that the current
i) lead the voltage when ω<1/√(LC)
ii) is in phase with the voltage when ω = 1/√(LC)
iii) lags the voltage when ω>1/√(LC)
what is the net impedance of the circuit when ω = 1/√(LC)?
