Question : A steady current of 2 A flows through a circular coil having 5 turns of radius 7 cm. The coil lies in X-Y plane with its centre at the origin. Find the magnitude of the magnetic dipole moment of the coil.
Doubt by Ananya
Solution :
Current (I) = 2 A
No. of turns (N) = 5
Radius of the coil (r) = 7 cm = 0.07 m
Area of the coil (A) = πr²
= (22/7)×0.07×0.07
= 154×10-4 m²
= (22/7)×0.07×0.07
= 154×10-4 m²
= 1.54×10-2 m²
Magnetic Dipole Moment (m)
m = NIA
m = 5×2×154×10-2
m = 0.154 Am²
m = 0.154 Am²
