Question : A pair of concentric coils having radius 1 cm and 2 cm has a mutual inductance of 1.5 H. If the current in outer coil changes from 0 to 20 A in 0.5 second, what is (a) the change in flux linkage with the inner coil & b) self-inductance of outer coil?
Doubt by Ananya
Solution :
r1 = 1 cm = 10-2 m
r2 = 2 cm = 2×10-2 m
M = 1.5 H
In outer coil
dI=20-0 = 20 A
dt = 0.5 s
a) We know,
ϕ=MI
ϕ=MI
differentiating both sides
dϕ=MdI
change in flux (dϕ)
= MdI
= 1.5×20
= 30 Wb
= MdI
= 1.5×20
= 30 Wb
b) We know
ϕ=LI
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