Question : Figure Shows a plot of current I through the cross section of a wire over a time interval of 10s. Find the amount of charge that flows through the wire during this time period.
Doubt by Kunal
Solution :
We know,
Area undert I vs t graph will give
= Current (I)× time (t)
= Charge (q)
So, amount of charge flows through the wire in 10 seconds
= area under I-t graph
= area of Trapezium
= ½ × (Sum of parallel side)× Height
= ½ × [(10-5)+(10-0)]×(5-0)
= ½ ×(5+10)×5
= ½×75
= 37.5 A
