In hydrogen atom, an electron moves in an orbit of radius 5.0×10-11 m with a speed of 2×106 m/s. Find the . . .

Question : In hydrogen atom, an electron moves in an orbit of radius 5.0×10^-11 m with a speed of 2×10⁶ m/s. Find the equivalent current. (Electric charge = 1.6×10^-19 C) 

Doubt by Mohini

Solution : 

Here
N = 1
q = Ne
q = 1×1.6×10^-19 C
q = 1.6×10^-19 C

r = 5.0×10^-11 m
v = 2×10⁶ m/s

We know,
I = q/t
I = q/[(2πr)/v]
I = qv/2πr
I = [(1.6×10^-19)×(2×10⁶)]/[2×(22/7)×5.0×10^-11]
I = 2.1 mA