Question : An electric circuit is shown in the figure. Calculate the potential difference across the resistor of 400 Ohm, as will be measured by the voltmeter V of resistance 400 Ohm.
Doubt by Mohini
Solution :
If we look closer than we can see that 400 Ω resistor and 400 Ω voltmeter both are connected in parallel so their equivalent resistance would be
=(400×400)/(400+400)
=(400×400)/800
= 200 Ω
=(400×400)/(400+400)
=(400×400)/800
= 200 Ω
Now If we drawn the equivalent diagram of the circuit then we realise that it becomes a balanced wheat stone bridge as shown below.
Now the equivalent resistance of balanced wheat stone bridge would be
Req=(300×300)/(300+300)
Req=(300×300)/600
Req = 150 Ω
Current drawn from the battery, I = V/Req
I = 10/150
I = (1/15) A
Current through ABC or Current through ADC = I/2
= (1/15)/2
= (1/30) A
= (1/15)/2
= (1/30) A
Now, Voltage drop across the branch BC
= current × Resistance (BC)
= (1/30)×200
= current × Resistance (BC)
= (1/30)×200
=20/3 V
=6.666 V
= 6.67 V
=6.666 V
= 6.67 V