A conducting square loop of side 'L' and resistance 'R' moves in its . . .

Question :  A conducting square loop of side 'L' and resistance 'R' moves in its plane with a uniform velocity 'V' perpendicular to one of its sides. A magnetic induction 'B' constant in time and space pointing perpendicular and into the plane of the loop exists everywhere as shown in the figure. The current induced in the loop is 

a) BLV/R Clockwise

b) BLV/R Anticlockwise

c) 2BLV/R Anticlockwise

d) Zero

Doubt by Tushar

Solution : 

According to Faraday's Laws of Electromagnetic Induction

ε = -dΦ/dt
ε = -d(BAcosθ)/dt
[∵Φ = BAcosθ]

Here 
B = constant 
A = constant 
cosθ = constant

so Φ = const. 

As we know, differentiation of constant is always zero.

so induced emf will be zero

ε=0

Induced current,
I= ε/R 
= 0/R

= 0

Hence, d) would be the correct option.