Question : A thin metallic spherical shell of radius R carries a charge Q on its surface. A point charge Q/2 is placed at its center C and another charge +2Q is placed outside the shell at a distance x from the centre as shown in the figure.
a) Find the electric flux through the shell.
b) Find the force on the charges at the centre C of the shell and at a point A.
Doubt by Aditya
Solution :
a) Charge enclosed by the spherical shell (qnet) = Q/2
According to Gauss's Theorem
Electric flux (ɸE) = qnet/ε₀
Electric flux (ɸE) = qnet/ε₀
ɸE=(Q/2)/ε₀
ɸE=Q/2ε₀
ɸE=Q/2ε₀
b) We know,
Electric field inside a charged spehrical shell is Zero.
Force experienced by charge Q/2 at the centre C will be given by
Electric field inside a charged spehrical shell is Zero.
Force experienced by charge Q/2 at the centre C will be given by
Force = charge × Electric field
FC=(Q/2)×0
FC = 0
FC=(Q/2)×0
FC = 0
We know,
Electric field due to a charged spherical shell at any point outside the spherical shell is given by
Electric field due to a charged spherical shell at any point outside the spherical shell is given by
E=kq/r²
EA=k(Q+Q/2)/x2
EA=k(3Q/2)/x2
Force experience by the charge 2Q at A will be
FA=(2Q)×k(3Q/2)/x2
FA=k3Q²/x²
FA=(1/4πε₀)(3Q2/x2)
FA = 3Q2/4πε₀x2
EA=k(Q+Q/2)/x2
EA=k(3Q/2)/x2
Force experience by the charge 2Q at A will be
FA=(2Q)×k(3Q/2)/x2
FA=k3Q²/x²
FA=(1/4πε₀)(3Q2/x2)
FA = 3Q2/4πε₀x2