
Doubt by Riddhi
Solution :
We know,
Electric Potential due to an isolated charge particle q is given by
V=kq/r
If q is +ve then as r increases the value of electric potential will decrease.
If q is -ve then as r increases the value of electric potential will increases.
As shown in our question as distance r increases from the charge the magnitude of electric potential increase, it means the polarity of charge q is -ve.
Electric field lines due to a charge -q will be radially inward i.e. directing from higher potential to lower potential because we know that the electric potential always decreases in the direction of electric field as shown below.
