Question : Determine the electric dipole moment of the system of three charges placed on the vertices of an equilateral triangle as shown in the figure.
a)√3ql(j-i)/√2
b) 2qlj
c) -√3qlj
d) ql(i+j)/√2
Solution :
Here
p=ql
Direction of Dipole Moment is from -ve charge to +ve charge as shown in the figure.
p=ql
Direction of Dipole Moment is from -ve charge to +ve charge as shown in the figure.
Resolving the dipole moment p into two rectangular components pcosθ and psinθ as shown in the figure.
So Resultant dipole moment
pNET = 2pcosθ
=2(ql)cos30°
=2ql(√3/2)
=√3 ql
As seen in the figure, the resultant direction will be towards -ve z-axis (-j)
So the final answer will be -√3qlj.
Hence c) -√3qlj will be the correct option.
So Resultant dipole moment
pNET = 2pcosθ
=2(ql)cos30°
=2ql(√3/2)
=√3 ql
As seen in the figure, the resultant direction will be towards -ve z-axis (-j)
So the final answer will be -√3qlj.
Hence c) -√3qlj will be the correct option.