Problem : Two conducting sphere of radii 6 cm 12 cm each having the same charge 3 × 10-8C, are kept very far apart. If the sphere are connected to each other by a conducting wire, find
a) the direction and amount of charged transferred and
b) find potential of each sphere.
Doubt by Meghna
Solution :
We know.
V = kq/r
V∝ 1/r
The sphere of smaller radius has large potential then the sphere of large radius. Hence charges will flow from small sphere of 6 cm radius to large sphere of 12 cm radius. .
These charges will keep on flowing until the potential becomes equal.
q1 = C1V
q2 = C2V
We know,
q ∝ C ∝ r
q = q1 + q2 = 2q1 = 2q2
r1 = r
r2 = 2r
q1' = [r1/(r1+r2)]q = [q/3] = 2q1/3
q2' = [r2/(r1+r2)]q = [2q/3] = 4q1/3
Total Change Transferred
= q1-2q1/3 = q1/3 = 10-8 C
Common Potential (VC) = [(C1V1+C2V2)]/(C1+C2)
= (q1+q2)k/r1+r2
= 2qk/3r
= (6 × 10-8 × 9 × 109)/3×6 ×10-2
= 3 × 103 V
= 3000 V