Question : A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is
a) F1-F2+F3
b) F1-F2-F3
c) √[(F3-F1)2+F22]
d) √[(F3-F1)2-F22]
Doubt by Maansvi
Solution :
F2 = F4 Sinθ — (1)
F3 - F1 = F4 Cos θ — (2)
Squaring and adding equation (1) and (2)
F22 + (F3-F1)2 = F42
F4 = √[(F3-F1)2+F22]
(c) is correct option.
F2 = F4 Sinθ — (1)
F3 - F1 = F4 Cos θ — (2)
Squaring and adding equation (1) and (2)
F22 + (F3-F1)2 = F42
F4 = √[(F3-F1)2+F22]
(c) is correct option.
