Question : A ray of light incident at an angle θ on a refracting face of a prism emerges from the other face normally. If the angle of the prism is 5° and the prism is made of a material of refractive index 1.5, the angle of incidence is
a) 7.5°
b) 5°
c) 15°
d) 2.5°
Doubt by Saif
Solution :
Here
Refractive Index of Prism (µ) = 1.5
Angle of Prism (A) = 5°
Angle of Prism (A) = 5°
Angle of incidence (i) = θ
Here, r2=e=0°
We know,
r1+r2=A
r1+0°=5°
r1=5°
r1+r2=A
r1+0°=5°
r1=5°
Applying Snell's Law
µ=sini/sinr
µ=sini/sinr
µ=i/r [∵ Since Angles are small]
µ=θ/r1
1.5=θ/5°
7.5°=θ
µ=θ/r1
1.5=θ/5°
7.5°=θ
θ=7.5°
Hence, a) 7.5°, would be the correct option.