Question : A thin disc of radius b=2a has a concentric hole of radius a in it (See Figure). It carries uniform surface charge σ on it. If the electric field on its axis at height h (h<<a) from its centre is given as Ch then value of C is
a) σ/aε₀
b) σ/2aε₀
c) σ/4aε₀
d) σ/8aε₀
Doubt by Eshani
Solution :
Before Solving This Question, you have to derive the expression for Electric field due to a disc having surface charge density σ.
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